This is a famous problem from 1882, to which a prize of $1000 was awarded for the best solution. The task is to arrange the seven numbers 4, 5, 6, 7, 8, 9, and 0, and eight dots in such a way that an addition approximates the number 82 as close as possible. Each of the numbers can be used only once. The dots can be used in two ways: as decimal point and as symbol for a recurring decimal. For example, the fraction 1/3 can be written as
.
. 3
The dot on top of the three denotes that this number is repeated infinitely. If a group of numbers needs to be repeated, two dots are used: one to denote the beginning of the recurring part and one to denote the end of it. For example, the fraction 1/7 can be written as
. .
. 1 4 2 8 5 7
Note that '0.5' is written as '.5'.
How close can you get to the number 82?
I'm posting one puzzle, riddle, math, or statistical problem a day. Try to answer each one and post your answers in the comments section. I'll post the answer the next day. Even if you have the same answer as someone else, feel free to put up your answer, too!
Monday, April 25, 2011
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What, no takers?
ReplyDelete.
80.5
..
.97
..
.46
_____
82
Well, that wasn't formatted very well. The first . is over the 5 in 80.5. The two dots under 80.5 should be directly over the 97. The two dots over .46 should be directly over the 46.
ReplyDelete80. (and then)
ReplyDelete... .
97645
^ Written around the same time, though took awhile to post due to dot formatting problems too. (Whatever the case, my answer was not entirely correct. Enjoy your day...)
ReplyDelete