A man was walking down a road carrying a basket of eggs. As he is walked he met someone who buys one-half of his eggs plus one-half of an egg. A little further and meets another person who buys one-half of his eggs plus one-half of an egg. Later he meets another person who buys one-half of his eggs plus one half an egg. At this
point he has sold all of his eggs, and he never broke an egg. How many eggs did the man have to start with?
I'm posting one puzzle, riddle, math, or statistical problem a day. Try to answer each one and post your answers in the comments section. I'll post the answer the next day. Even if you have the same answer as someone else, feel free to put up your answer, too!
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7 eggs
ReplyDeleteseven
ReplyDeleteoookay... i did some math in an equation... but somehow i keep getting -7. He must have had eggs made of anti-matter. >_<
ReplyDeleteNo anti-matter allowed! ;-) We're talking farmers, not physicists!
ReplyDeleteIn that case I am going to multiply my basket of eggs by -1 so i can get 7
ReplyDeleteNo eggs.
ReplyDeleteAlrighty then. 7 it is.
ReplyDeleteAt the beggining, someone buys 3.5 + .5 = 4 eggs, leaving 3. Then someone buys 1.5 + .5 = 2 eggs, leaving 1. Then someone buys .5 + .5, leaving him with none.
No eggs doesn't work. If he 0, then 1/2 of 0 = 0 + .5 would be .5 eggs.
Ok... i think i know what i did wrong... I dropped a - sign somewhere when i did mine.
ReplyDelete0=X + -1(X/2+.5) + -1((x/2+.5)/2+.5) + -1(((x/2+.5)/2+.5)/2+.5)
Or i just got a 7 by luck