I'm posting one puzzle, riddle, math, or statistical problem a day. Try to answer each one and post your answers in the comments section. I'll post the answer the next day. Even if you have the same answer as someone else, feel free to put up your answer, too!
Tuesday, August 30, 2005
Pistols at Dawn
You're in a pistol duel with two others. You have shoot with an accuracy of 33%. The other two shoot with an accuracy of 100% and 50%, respectively. The rules of the duel are one shot per-person per-round. the shooting order is from worst shooter to best shooter. Thus, you go first, the 50% guy goes second, and the 100% guy goes third; repeat until only one is left. If someone is hit, we just skip his or her turn. What should you shoot at in round 1 to maximize your chances of survival over time?
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You are A, 1/3 accuracy
ReplyDeleteB is 1/2 accurate
C is always accurate
x X y = x shoots at y
As A, you can either:
1) shoot at B
2) shoot at C
3) shoot at the ground (deliberately miss).
1) a X b
if you hit (1/3 of the time), you lose, and C fires next and takes you out
otherwise (2/3 of the time) b X c as C is B's biggest threat. 1/2 the time B takes out C, which leaves a X b to resolve. 1/2 the time B misses, C kills B, and you have 1/3 chance to take out C before he takes you out.
First, a X b (with C out of the picture) is
1/3 + 2/3 * 1/2 * 1/3 + 2/3 * 1/2 * 2/3 * 1/2 * 1/3 + ...
= 1/3 + (1/3)^n * 1/3
= 1/3 + 1/6 = 1/2
So a X b (with C there) is
2/3 * 1/2 * 1/2 + 2/3 * 1/2 * 1/3 = 10/36 chance of winning
2) a X c
if you hit C, B shoots are you, 1/2 the time you survive and it boils down to the a X b (C out of picture) calculated above.
if you miss C, B shoots at C, 1/2 the time hits and it boils down to a X b above. 1/2 the time B misses, C takes B out, and you have 1/3 chance to take C out.
So a X c is
1/3 * 1/2 * 1/2 + 2/3 * 1/2 * 1/2 + 2/3 * 1/2 * 1/3
= 1/12 + 1/6 + 1/9 = 13/36 chance of winning
This makes sense, relatively, as you best hope is to take out the most accurate shooter.
3) option 3, you skip your turn by firing into the ground.
b X c, 1/2 the time B hits and it becomes a X b calculated above. The other 1/2, C takes out B and you have 1/3 chance to take out C.
So, A miss on purpose is
1/2 * 1/2 + 1/2 * 1/3 = 1/4 + 1/6 = 15/36 chance of winning.
So your best option, at 15/36 = 41.7% of winning, is to miss your first shot on purpose!!